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20x^2=10000
We move all terms to the left:
20x^2-(10000)=0
a = 20; b = 0; c = -10000;
Δ = b2-4ac
Δ = 02-4·20·(-10000)
Δ = 800000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{800000}=\sqrt{160000*5}=\sqrt{160000}*\sqrt{5}=400\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400\sqrt{5}}{2*20}=\frac{0-400\sqrt{5}}{40} =-\frac{400\sqrt{5}}{40} =-10\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400\sqrt{5}}{2*20}=\frac{0+400\sqrt{5}}{40} =\frac{400\sqrt{5}}{40} =10\sqrt{5} $
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